What is the equation of the line that passes through (1, 2/3) and (-1,-1)?

a. y=-6x+5
b. y=5/6-1/6
c. y=2/3x+1/5
d. y=6/5x+1/5

(1,2/3)(-1,-1)
slope = (-1 - 2/3) / (-1-1) = (-3/3 - 2/3) / -2 = (-5/3)/-2 = -5/3 * -1/2 = 5/6

y = mx + b
slope(m) = 5/6
(-1,-1)...x = -1 and y = -1
now we sub
-1 = 5/6(-1) + b
-1 = -5/6 + b
-1 + 5/6 = b
-6/6 + 5/6 = b
-1/6 = b

y = 5/6x - 1/6 <=== ur equation