How do I solve this problem using the substitution method
x-3y=4
4x-2y=26

x=7

y=1

Step-by-step explanation:

In order to use substitution you need to get one of the equations to have a variable by itself. I'm going to use the first one and get x by itself.

x-3y= 4  So firstly add the 3y to both sides since you want x alone.

 +3y  +3y

x=3y+4

Now that you have x alone you can plug this into the second equation for x.

4(3y+4)-2y=26

Next distribute the 4 to both terms inside the parenthesis.

4(3y)+4(4)-2y=26    Simplify.

12y+16-2y=26         Now add or subtract your like terms together (12y-2y).

10y+16=26              Next subtract 16 from both sides.

     -16  -16

10y=10                   Finally, to get y alone divide by 10 on both side.

y=1

To find x you plug y back into one of the equations you started with. I'm using x-3y=4  Again.

x-3(1)=4        Distribute the -3 to the one.

x-3=4           Now add 3 to both sides.

+3 +3

x=7

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

answer: ♡♡♡♡♡♡♡♡♡♡

step-by-step explanation: