A company is developing a new high-performance wax for cross country ski racing. In order to justify the price marketing wants, the wax needs to be very fast. Specifically, the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion. To test it, the champion will ski the course 8 times. The champion's time (selected at random) 57.9, 62.9, 50.6, 50.5, 48.2, 47.2, 50.2, and 43.1 seconds to complete the test course.1. Should they market the wax? Assume the assumptions and conditions for appropriate hypothesis testing are met for the sample. Assume (Sig=0.05). what is the null and alternative hypothesis? Choose the correct answer below. A) H0: u=55 vs. HA: u>55B) H0: u>55 vs. HA: u=55C) H0: u<55 vs. HA: u=55D) H0: u=55 vs. HA: u<552.What is the value of the test statistic?

A)Yes they should market the wax, because it melts before 55 seconds

C) Null hypothesis: mean <55 vs. Alternative hypothesis :mean =55

D) the value is 51.33 seconds

Step-by-step explanation:

The selected samples for the champion are : 57.9, 62.9, 50.6, 50.5,48.2,47.2,50.2 and 43.1

The mean is ;

Sum =57.9 + 62.9 + 50.6 + 50.5+48.2+47.2+50.2+ 43.1 =410.6

Mean= 410.6/8 =51.33= mean

Assuming Significant =0.05 thus applying this level will give you 51.28-51.38

if specifically, the mean time to finish their standard test course should be less than 55 seconds for a former Olympic champion, then the null hypothesis is correct

Then;

Null hypothesis: mean <55

Alternative hypothesis :mean =55

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

happy to

pls mark as brainliest

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

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