If f(x) and it's inverse function, f-1(x), are both plotted on the same coordinate plane, what is there correct point of intersection? (0,-2) (1,-1) (2,0) (3,3)

The plot coordinates are (3,3).

Step-by-step explanation:

Given:

A fucntion f(x) and its inverse is f-1(x)

To find :

The plot of the coordinates for the intersection.

Solution:

Now we know that inverse fucntion is changing the y=f(x) and then

changing to x to y and y to x

So given function is f(x)

Inverse function is y,

But value of inverse function is f-1(x)

So y=f(x)=f-1(x)

Therefore it becomes

y=x

Hence the value is y=x coordinates

i.e. (3,3)

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

the olimpics is not going to wokk out

step-by-step explanation: