The number of accidents per week at a hazardous intersection varies with mean 2.2 and standard deviation 1.4. This distribution takes only whole-number values, so it is certainly not a normal distribution. Let "x-bar" be the mean number of accidents per week at the intersection during a year (52 weeks). What is the approximate probability that there are fewer than 100 accidents in a year? (Hint: Restate this event in terms of "x-bar")

The approximate probability that there are fewer than 100 accidents in a year = .9251

Step-by-step explanation:

Given -

Mean =2.2

Standard deviation = 1.4

Let  be the mean number of accidents per week at the intersection during a year (52 weeks)

Then = = 1.92

the approximate probability that there are fewer than 1.92 accidents per week  in a year

[Z   = ]

=    = (

 = P( )   ( Using Z table)

=  .9251

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: