In a thunderstorm, the wind velocity in meters per second can be described by the function v(p) = 5.7 √998 - p, where p is the air pressure in millibars. What is the air pressure of a thunderstorm in which the wind velocity is 49.3 meters per second?

923.1927 millibars

Step-by-step explanation:

The wind velocity is given by the function:

#We make p the subject of the formula:

#Substitute the given values in the function above to solve for p;

Hence, the air pressure is 923.1927 millibars.

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4