What is the solution set of 6x^2 - 24 = 0? .

a.) {-2, 2}
b.) {-2}
c.) {2}

If xy=0 then assume taht x and/or y=0

remember differnce of 2 perfect squares
a^2-b^2=(a-b)(a+b)

factor
6x^2-24=0
6(x^2-4)=0
6(x^2-2^2)=0
6(x-2)(x+2)=0
set to zero

x-2=0
x=2

x+2=0
x=-2

x=2 and -2

A is answer

We are given with the expression 6x^2 - 24 = 0. We are asked in the problem for its solution set. The first step to take is to factor out 6 in the equation resulting to x^2 - 4 = 0. This is a special type of equation where after factoring the equation becomes (x-2)*(x+2) = 0. Hence the solution set is A. {-2,2}

It says in the questions that it is 6.5?