Ahorse race has 13 entries. assuming that there are no ties, what is the probability that the four horses owned by one person finish first, second, third and fourth?

The solution would be like this for this specific problem:

4/13 * 3/12* 2/11 * 1/10 = 0.0014

So the probability that the four horses owned by one person finish first, second, third and fourth is 0.0014. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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