Mathematics, 03.04.2020 21:17 21marmong
A quarterback throws a football toward a receiver from a height of 6 ft. The initial vertical velocity of the ball is 14 ft/s. At the same time that the ball is thrown, the receiver raises his hands to a height of 8 ft and jumps up with an initial vertical velocity of 10 ft/s.
Projectile motion formula:
h = -16t2 + vt + h0
t = time, in seconds, since the ball was thrown
h = height, in feet, above the ground
{
Complete the system that models the heights of the ball and the receiver’s hands over time.
h = -16t² + 14t +
6
h = -16t² +
10
t
+
8
After
seconds, the receiver's hands and the ball will be at the same height.
Answers: 1
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