The lengths of a certain species of beetles are normally distributed with a mean of 1.9 centimeters and a standard deviation of 0.2 centimeters.

What is the z-score of a beetle of this species with a length of 2.38 centimeters?

the z score is 2.4

Step-by-step explanation:

Since the lengths of the certain species of beetles are normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = length of the beetle species.

µ = mean length

σ = standard deviation

From the information given,

µ = 1.9 centimeters

σ = 0.2 centimeters

For a species with a length of 2.38 centimeters, the z score is

z = (2.38 - 1.9)/0.2

z = 0.48/0.2

z = 2.4

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

pretty sure 750 each month!

step-by-step explanation: