Find the equation of the straight line that has slope m = -6 and passes through point (2, -7)

y

=

3

2

x

+

1

Explanation:

To find the slope  

(

m

)

of the straight line that passes through two points  

(

x

1

,

y

1

)

and  

(

x

2

,

y

2

)

apply:

(

y

1

−

y

2

)

=

m

(

x

1

−

x

2

)

In this example our two points are  

(

0

,

1

)

and  

(

2

,

4

)

Hence:  

(

1

−

4

)

=

m

(

0

−

2

)

−

3

=

−

2

m

→

m

=

3

2

The equation of a straight line in slope  

(

m

)

and intercept  

(

c

)

form is:

y

=

m

x

+

c

In this example:

y

=

3

2

x

+

c

Since the point  

(

0

,

1

)

is on this line  

→

1

=

0

+

c

Hence,  

c

=

1

∴

y

=

3

2

x

+

1

is our required straight line.

Step-by-step explanation:

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10

1696 hundred thousand

step-by-step explanation: