What is the solution to StartFraction 5 over 6 EndFraction x minus one-third greater-than 1 and one-third? x > StartFraction 25 over 18 EndFraction x < StartFraction 25 over 18 EndFraction x > 2 x < 2

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.

y=sec x is the correct answer

~batmans wife dun dun