: Maria attended a Chicago Cubs baseball game last night. The ticket to get into the game was $39.00 and hot dogs cost $5.50 each. Maria had at most $60 to spend for a ticket and as many hot dogs she could buy without overspending. What is the most number of hot dogs Maria could buy at the baseball game without overspending?

3

Step-by-step explanation:

At first you would subtract 39 from 60. Then you would do 21/5.5 and you would get 3.818… and due to the fact you can't go over 60 you would round to 3 and not 4

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb