HALP
Based on the results of the simulation, if 115 groups are formed, about how many of them would you expect to contain at least two freshmen? Round your answer to the nearest number of groups.

18 groups

23 groups

15 groups

12 groups

i would say 18

Step-by-step explanation:

out of the letters you gave us only 5 groups out of 25 had 2 freshmen in them if it continues then for each 25 groups 5 will have 2 freshmen so at 50 its 10 at 100 its 15 and at 115 it would be about 18

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm