A ball is thrown into the air with an initial upward velocity of 48 ft/s. It's height h in feet after t seconds is given by the function h(t)= -16t^2 + 48t +4

Time taken for the ball to hit the ground back = 3.08 s

Step-by-step explanation:

h(t)= -16t² + 48t + 4

when will rhe object come back to hit rhe ground?

When the ball is at the level.of the ground, h(t) = 0.

0 = -16t² + 48t + 4

-16t² + 48t + 4 = 0

Solving the quadratic equation

t = 3.08 s or t = -0.08 s

Since the time cannot be negative,

Time taken for the ball to hit the ground back = 3.08 s

Hope this Helps!!!

do have an equation or graph or

step-by-step explanation: