A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rate v=0.375⋅10−9 m3 per unit time. Use differentials to estimate the maximum error in the viscosity η given by

η=π8pr4v

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

The implicit derivative with respect to the time would be

If we multiply everything by    dt   we get  

Remember that  the error is given by     therefore doing some algebra we get that

Since,    r = 0.006   ,   dr = 0.00025 ,  p = 4*105   ,   dp = 2000  we get that

Which means that  the maximum error for viscosity is 17.14%.  

answer

the correct answer is

explanation

the given function is

the excluded values are obtained by solving:

we factor to obtain:

the excluded values are