Find the equation of a parabola with vertex (3, 5) and directrix y = 7.

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step-by-step explanation:

1. a^4+8a^3+24a^2+32a+16

2.y^8+8y^7+28y^6+56y^5+70y^4+56y^3+28y^2+8y+1

3.x^6-3x^4y^2+3x^2y^4-y^6

6-3=3

3*3=9

9+12=21

21/3=7

7*8=56

56 is your answer