A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. How much water must be added to accomplish this task? (cc stands for cubic centimeters)

The amount of water must be added to this task = 60

Step-by-step explanation:

Let amount of water added = x

Then from the given conditions

A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. So

90 (0.05) = 0.03 ( 90 + x )

4.5 = 2.7 + 0.03 x

0.03 x = 1.8

x = 60

Therefore the amount of water must be added to this task = 60

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

it’s the first one your welcome