An automobile insurance company claims that its rates for teenage drivers average $410 less per year than the same coverage from another company.
In a random sample of 35 customers, the average savings was $390 per year, with a standard deviation of $55 per year. What is the z-value rounded to the nearest hundredth? Is there enough evidence to reject the claim?

Z-value is -2.15.

Yes, It is enough evidence to Reject the claim.

Step-by-step explanation:

Given that,

Rate for teenage drivers average $410 less per year than the same coverage from another company. total number of customers are 35 and their average saving $390 per year. its standard deviation is $55.

To find :- What is the z-value rounded to the nearest hundredth ? is there enough evidence to reject the claim ?

so,  

               Z- value =

Here,    ,    ,    ,  

calculating the Z-value,

                Z-value =

                             =  

                             =

Now, for rejecting the claim we need to find the P- value

(a) p value is used in hypothesis testing to find the support or reject of null hypothesis.

(b) the smaller p - value gives a strong evidence that you can reject the null hypothesis.

              P value =

Here we get that the P value is smaller than .    ()

Hence,

Yes, It is enough evidence to Reject the claim.

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c