Whats the twentieth term of this arithmetic sequence: a sub 1= 3 and d=7

Arithmetic Sequence

The value of the 20th term of this arithmetic series is 136

Step-by-step explanation:

The first term of the arithmetic term is a = 3                                                                                  

and the common difference is d = 7

So the 20th term of this arithmetic progression is given by

an = a + (n-1) × d  

where an is the nth term of the arithmetic progression

so for nth term, the value of  n = 20

⇒ a20 = 3 + (20-1) × 7

⇒ a20 = 3 + 19 × 7

⇒ a20 = 3 + 133  

⇒ a20 = 136  

Hence ,the value of the 20th term of this arithmetic series is 136  

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47