What is the slope of the line that passes through the points (-2, 3) and (-14, -5)

Slope = 2/3

Step-by-step explanation:

The equation of the line

y = mx + c

y = intercept point y

m = slope of the line

x = intercept point x

c = intercept of the line

The slope of the line

m = y2 - y1 / x2 - x1

Given

( -2 , 3) ( -14 , -5)

x1 = -2

y1 = 3

x2 = -14

y2 = -5

Insert the values

m = -5 - 3 / -14 - (-2)

= -8 / -14 + 2.

= -8 / -12

Minus cancels minus

= 8/12

Divide by 4

m = 2/3

The slope of the line is 2/3

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length