Chuck and Dana agree to meet in Chicago for the weekend. Chuck travels 104 miles in the same time that Dana travels 96 miles. If Chuck's rate of travel is 4 mph more than Dana's, at what speed does Chuck travel?

Chuck's travel at a rate of 52mph

Step-by-step explanation:

For Chuck's trip:

D=RT

104= (R+4)T

T= 104 / (R+4)

For Dana's trip:

96 = RT

T= 96/R

Set both equation for Chuck's and Dana together

104/(R+4) =96/R

Then we cross multiply

96(R+4) = 104R

96R + 384 = 104R

104R - 96R = 384

8R = 384

To get R, divide both side by 8

8R/8 = 384/8

R= 48mph

This means Dana's speed is 48mph

Chuck's speed will be: 48mph+4mph = 52mph

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24