Mathematics, 01.04.2020 19:41 shmote12
Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves according to the velocity equation v(t)= 6t2 - 18t + 12 (in feet/sec).
Answers: 3
. We are asked to find the distance that the particle will travel in its first 2 seconds.
![s(t)=[\frac{6t^3}{3}-\frac{18t^2}{2}+12t]^1_0 +[\frac{-6t^3}{3}+\frac{18t^2}{2}-12t]^2_1](/tpl/images/0575/9453/0c6f3.png)
![s(t)=[2t^3-9t^2+12t]^1_0 +[-2t^3+9t^2-12t]^2_1](/tpl/images/0575/9453/01c98.png)
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Find the distance, in feet, a particle travels in its first 2 seconds of travel, if it moves accordi...
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