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Mathematics, 01.04.2020 17:29 shiiIjustneedananswe
H(x) = \begin{cases} 8+6x & , & x<-7 \dfrac{10}{x+4} & , & -7\leq x<-5 4x-3 & , & x \geq -5\end{cases}h(x)= ⎩ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎧ 8+6x x+4 10 4x−3 , , , x<−7 −7≤x<−5 x≥−5 h(-5)=h(−5)=h, left parenthesis, minus, 5, right parenthesis, equals
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H(x) = \begin{cases} 8+6x & , & x<-7 \dfrac{10}{x+4} & , & -7\leq x<-5 4x-3 &...
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