A standard deck of 52 cards contains 4 suits: hearts, clubs, diamonds, and spades. Each suit consists of cards numbered 2 through 10, a jack, a queen, a king, and an ace.

Bashir decides to pick one card at random from a standard deck of 52 cards. Let F be the event that he chooses a face card(a jack, queen, or king of any suit) and S be the event that he chooses a spade.

what is P (F or S), the probability that the card Bashir chooses is either a face card or a spade?

Step-by-step explanation:

The total number of cards, n (C) = 52

Let F be the event that he chooses a face card(a jack, queen, or king of any suit)

The total number of cards in F event, n (F) = 3 * 4 (no of suits) = 12

S be the event that he chooses a spade,

The total number of cards in S event, n (S) = 13

n (A ∩ B) = 3

The probability that the card Bashir chooses is either a face card or a spade,

P (F or S) = [ n(F) + n(S) - n(F ∩ S) ] / n (C)

= [ 13 + 12 - 3 ] / 52

= 22 / 52 = 11 / 26

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3