Use the unit circle to find the value of cot (–270°). Question 3 options: cot (–270°) = 1 cot (–270°) = –1 cot (–270°) = 0 undefined

Question 3 options:

cot (–270°) = 1

cot (–270°) = –1

cot (–270°) = 0

undefined

cot(-270) = 0

Step-by-step explanation:

given cot ( -270)

In trigonometry function we will use cot ( -x) = -cotx

so cot (-270) = - cot270

trigonometry table

          II quadrant                                I quadrant ( All positive)                                                                              

 sin θ            90+θ                                                    90 -θ

 cosec θ     180-θ                                                   360+θ

            third quadrant                                fourth quadrant

 tan θ            180+θ                                       cos θ          270+θ

 cot θ       270 - θ                                          sec θ       360-θ                                    

Given

cot (-270) = -cot ( 270)

                = - cot ( 180 + 90) (third quadrant above table)

                = -cot 90 =0 ( cot θ positive in third quadrant

Final answer:-

cot(-270) =0

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)