If H=f of g and H(x) = sqrt 64 - 4x^2 which of the following cannot be the component functions f and g?

a.) f(x)=sqrt x ; g(x) = 64 - 4x^2
b.) f(x)=sqrt 64 - x ; g(x) = 4x^2
c.)f(x)=sqrt 64-4x ; g(x) = x^2
d. f(x)=sqrt 64-x^2; g(x)=4x

answer: i'm not sure

step-by-step explanation:

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

it is a secret for it not to be compromised sorry

step-by-step explanation:

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: