What is the maximum height attained by the ball?

y=25

Step-by-step explanation:

The keyword in the question is "maximum", this tells you that you are looking for the vertex,(turning point of the graph, the highest point of the of the parabola). Since they are asking for the maximum height, and "t" represents seconds, you must find the "y" value.

Standard quadratic form is:

ax^2+bx+c

Use the vertex formula:

x=-b/2a

to find the "x" value of the vertex, then plug that value into the original equation as a substitute for "x".

Given y= 40t-16t^2

a=16, b=40

x=-40/2(-16)

x= 5/4 (or 1.25)

So,

y= 40(1.25) - 16(1.25)^2

y = 25

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

step-by-step explanation: