Find all zeros and write in factored form
(x-5)(3x^2-8x+6) =0

x = 5,  4/3+i√2/3,  4/3-i√2/3.

Step-by-step explanation:

(x-5)(3x^2-8x+6) =0

This is in factored form already. 3x^2 - 8x + 6  cannot be factored, it is prime.

One zero is x = 5.

3x^2-8x+6 = 0     Using the quadratic formula:

x = [8 +/- sqrt (64 - 4*3*6]) / 6

x =  4/3 +/- sqrt (-8) / 6

x = 4/3 +/-   2sqrt2 i / 6

x = 4/3 +/-  i√2 / 3.

168

step-by-step explanation:

i am pretty sure that the answer is 168

19

step-by-step explanation: