After painting his porch, jamil has 1/4 of a can of paint remaining. The can has a radius of 8cm and a height of 20cm. He wants to pour the remaining paint into a smaller can for storage. The smaller can has a radius of 5cm. What does the height of the smaller can need to be to hold all of the paint

The height of small can need to be 12.8 cm to hold all the paint

Step-by-step explanation:

- Jamil had a 1/4 can of paint left

- The radius of the can is 8 cm and its height is 20 cm

- He wants to put the remaining paint into a smaller can with a

 radius of 5 cm

- We need to find the height of the smaller can

- The volume of the paint in the larger can is the same volume of paint

 will put in the smaller can

- Lets find the volume of the paint in the larger can

∵ The volume of the paint in the larger can = 1/4 its volume

∵ The can is shaped a cylinder

∵ Volume the cylinder = πr²h, where r is the radius of it and h its height

∵ r = 8 cm and h = 20 cm

∴ The volume of the paint =  cm³

- Same amount of paint will put in the smaller can

∵ r = 5 cm and V = 320π cm³

∴ 320π = π(5)²h

- Divide both sides by π

∴ 320 = 25 h

- divide both sides by 25

∴ h = 12.8 cm

* The height of small can need to be 12.8 cm to hold all the paint

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.

it would take 5 hours i think idk i'm not that good at math.can you me with my questions i need asap.