Three consecutive numbers have a sum of 366, what is the largest consecutive number of the three?

123

Step-by-step explanation: TO solve problems like this, you should assign a variable to the lowest number, lets just say n. From here, since we know the numbers are consecutive, we can see that the numbers are n, n+1, and n+2. Therefore:

n(first number) + (n+1)(second number) +(n+2) (3rd number) =366

>n+n+1+n+2=366

3n+3=366

3n=363

n=121

n+2=123

ok so what's the question?

step-by-step explanation: