A circular path 2 feet wide has an inner diameter of 950 feet. How much farther is it around the outer
edge of the path than around the inner edge? Round to nearest hundredth. Use 3.14 for it.
The outer edge of the path is
feet farther around than the inner edge.

12.56 feet

Step-by-step explanation:

Given: The width of the circular path= 2 feet

The inner diameter of circular path= 150 feet

Therefore, the inner radius of circular path=

Now, the outer radius= 75+2=77 feet

We know that the circumference=

Inner circumference=

Outer circumference=

The difference=

Hence, the outer edge of the path is 12.56 feet farther than the inner edge

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.