What is the slope of a line that passes through the points twenty three, nine and negative thirty two, fourteen

Slope formula: m = (y2 - y1) / (x2 - x1)

Point 1: (23, 9)

Point 2: (-32, 14)

Plug values into the slope formula and simplify to find m, the slope:

m = (14 - 9) / (-32 - 23)

m = 5 / -55

m = -1 / 11

The slope is -1 / 11.

Hope this helps!! :)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐