Write the point-slope form of the equation of the line that passes through the point (1, 3) and has a slope of 2. Include your work in your final answer. Type your answer in the box provided to submit your solution.

y - 3 = 2(x - 1).

Step-by-step explanation:

Point-slope form is

y - y1 =m(x - x1)

Here m (slope) = 2 , x1 =  1 and y1 = 3:

y - 3 = 2(x - 1).

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

use formula for the circle a=3.14

step-by-step explanation: