– 5x + 13y = -7
5x + 4y = 24
I
=

x = 4

y = 1

Step-by-step explanation:

The given system of simultaneous equations is expressed as

- 5x + 13y = -7 - - - - - - - - - - - - 1

5x + 4y = 24 - - - - - - - - - - - - - 2

The first step is to decide on which variable to eliminate. Let us eliminate x. We would eliminate x by adding equation 1 to equation 2. It becomes

13y + 4y = - 7 + 24

17y = 17

y = 17/17

y = 1

Substituting y = 1 into equation 2, it becomes

5x + 4 × 1 = 24

5x + 4 = 24

5x = 24 - 4

5x = 20

x = 20/5

x = 4

x = 4

y = 1

Step-by-step explanation:

-5x + 13y = -7

5x + 4y = 24

Equations like this are resolved simultaneously, and we'll have to decide whether to employ the ELIMINATION METHODS or the SUBSTITUTION METHODS.

Which ever method we feel fine to proceed with, we must ensure to take note of the operations such that we do not mix up the signs. (Very important).

Let's label the equations, for ease of operation.

-5x + 13y = -7 also rearranged as

13y - 5x = -7 I

5x + 4y = 24

4y + 5x = 24 II

Add up equation (I) and (II) to eliminate the values in x.

17y = 17

y = 17/17

y = 1

Substitute y=1 in equation (I)

13y - 5x = -7

13(1) - 5x = -7

13 - 5x = -7

-5x = -7 - 13

-5x = - 20

x = -20 / -5

x = 4

Therefore: x = 4; y = 1

3 is greater then both of those numbers