Sa se afle aria unui trapez oarecare cu bazele de 4cm si 18cm, iar laturile laterale de 13cm si 15cm. Va rog repede, dau coroana

132 cm²

Step-by-step explanation:

h² = 13² - x²

h² = 15² - (14 - x)²

169 - x² = 225 - (196 - 28x + x²) = 29 + 28x -x²

28x = 169 - 29 = 140

x = 5

h = √13² - x² = √169 - 25=√144 = 12

Area of Trapezoid: (4 + 18) x 12 / 2 = 132

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)