A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4 m below the water level. Assume the tank is large so the velocity of the water at the top of the tank is zero. The rate of flow from the leak is 2.53×10^−3 m3/min. Determine the diameter of the hole.

Therefore the diameter of the hole is m.

Step-by-step explanation:

Bernoulli's equation,

P₁ = P₂= atmospheric presser

= density

            [since P₁ = P₂]

                               []

Here  

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole = m/s

                                                                                  =14.28 m/s.

Given, the rate of flow from the leak is

Let the diameter of the hole be d.

Then the cross section area of the hole is

We know that,

The rate of flow = Cross section area × speed

Therefore the diameter of the hole is m.

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

i am not sure :

step-by-step explanation: