Carlos has taken an initial dose of a prescription medication.
The relationship between the elapsed time t, in hours, since he took the first dose, and the amount of
medication, Mt). in milligrams (mg), in his bloodstream is modeled by the following function.
M(t) = 20.e-0.86
In how many hours will Carlos have 1 mg of medication remaining in his bloodstream?
Round your answer, if necessary, to the nearest hundredth

3.48 hours

Step-by-step explanation:

The equation is:

Where

M(t) is the amount of medication remaining in mg

t is the time it takes, in hours

The questions asks HOW LONG it will take to make the remaining medication to 1 milligrams (1 mg)??

We have to substitute M(t) with "1" and find the corresponding value of "t". We will use natural log to solve this. Shown below:

Note: Ln(e) = 1

This means, the amount of time it will take is about 3.48 hours

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64