In the U. S., 95% of children have received their DTaP vaccine. Calculate the probability that fewer than 700 out of a sample of LaTeX: n = 750n=750 children received their DTaP vaccine.

Using the normal approximation to the binomial, it is found that there is a 0.0146 = 1.46% probability that fewer than 700 children received their vaccine.

In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

In this problem:

For the approximation, the mean and the standard deviation are given by:

Using continuity correction, the probability that fewer than 700 children received their vaccine is P(X < 700 - 0.5) = P(X < 699.5), which is the p-value of Z when X = 669.5.

has a p-value of 0.0146.

0.0146 = 1.46% probability that fewer than 700 children received their vaccine.

A similar problem is given at link

0.0183

Step-by-step explanation:

The percentage of students, who received their DTaP vaccine is 95%.

This implies that:

and

The standard deviation of the proportion is

We want to find the probability, that the sample proportion,

im pretty sure its

(8,15)

step-by-step explanation:

answer: x=60