Trevor, robert, and maurice made some paper airplanes and want to see how far they will fly. the distance from trevor to robert is 13.5 feet. the distance from robert to maurice is 14.2 feet. the distance from maurice to trevor is 6.6 feet. find the measures of the three angles in the triangle.

a. m∠t=82.2, m∠r=27.4, m∠m=70.4

b. m∠t=27.4, m∠r=70.4, m∠m=82.2

c. m∠t=70.4, m∠r=82.2, m∠m=27.4

d. m∠t=60, m∠r=60, m∠m=60

a. m∠T=82.2, m∠R=27.4, m∠M=70.4

Step-by-step explanation:

Let T, R and M represent the position of Trevor, Robert, and Maurice respectively,

Given,

TR = 13.5 feet,

RM = 14.2 feet,

TM = 6.6 feet,

Since, TRM forms a triangle, ( because sum of any two sides is greater than third side )

By the law of cosine,

By substituting the values,

Similarly,

Hence, option 'a' is correct.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐