Uppose two equally matched baseball teams (Team A and Team B) are playing in a World Series in which the winner is the 1st team to win 4 games. After 2 games, the series must be halted due to unforeseen circumstances. At that time, Team A leads Team B (2 games to 0 games). The Baseball Commissioner decides to divide the $36.4 million that would normally go to the winner between the two teams. He calculates P(Team A would have won the series) and P(Team B would have won the series) assuming that the teams are exactly evenly matched. He divides the money up proportionately using these probabilities. How much money should Team A receive?

Team A should receive $29.57 million. The rest should go to team B

Step-by-step explanation:

Lets see, in order for team A to win the series, it needs to win 2 more games from a total of 5 remaining (this is a best of seven. We are assuming that all seven games are being played even if the series is finished; that shouldnt change the probability that team A wins the series).

Since both teams are even, the probability for team A to win a game is 0.5. We assume that 2 different matches are independent within each other, so the total amount of games that teams A would have won if the series would have continued is a binomial random variable, lets call it X, with parameters n=5, p=0.5. We want to know the probability that X is equal or greater than 2, that is, X=2, X=3, X=4 or X=5.

Therefore

This means that Team A should receive 81.25% of the money, that is 0.8125*36.4 = $29.57 million. The rest would go to team B.

the answer is 5636.7

.19875994384

step-by-step explanation:

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