A supplies box contains 3 red crayons, 2 green crayons, and 6 blue crayons. If we choose a crayon, then another crayon without putting the first one back in the supplies box, what is the probability that the first crayon will be red and the second will be blue? Are these events independent or dependent?

 3/11 & 6/10

Step-by-Step explanation:

there are 11 crayons, 3 of which are red so the chance of picking a red one is 3 out of 11. now that you have taken out a crayon you take the original number and take away 1

11 - 1 = 10

so the chance of taking a blue canyon out is 6/10.

these events are dependent because if you didn't take the first crayon out of the supply box the answer would be 6/11 instead of the 6/10 we have

answer: yes, he is correct

step-by-step explanation: 10x-1=59

                                              1-1=0     59+1=60

60/10=x=6

omg what happend to your question? if you could edit this question i can

step-by-step explanation: