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Mathematics, 31.03.2020 01:32 mayamcmillan11

Prove: The square of a number that is one more than a multiple of 3 is also one more than a multiple of 3.
(3n + 1)^2= 9n^2 +6n+1
= ? (?n^2 + ?n) + ?
= 1 more than multiple of 3

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