The manufacturer of cans of salmon that are supposed to have a net weight of 6 ounces tells you that the net weight is actually a normal random variable with a mean of 6.02 ounces and a standard deviation of 0.15 ounce. Suppose that you draw a random sample of 28 cans. Find the probability that the mean weight of the sample is less than 6.01 ounces.

0.3605 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 6.02 ounces

Standard Deviation, σ = 0.15 ounce

Sample size, n = 28

We are given that the distribution of weight of can is a bell shaped distribution that is a normal distribution.

Formula:

Standard error due to sampling =

P(weight of the sample is less than 6.01 ounces)

Calculation the value from standard normal z table, we have,  

0.3605 is the probability  that the mean weight of the sample is less than 6.01 ounces.

just take the area of the square and then the area of the circle then subtract the circle area from the squares area

step-by-step explanation: