1. Prove that the value of the expression a^2–a is divisible by 2 for any whole value of a.
2. Prove that the sum of three consecutive exponents of the number 2 is divisible by 14.

in steps

Step-by-step explanation:

1.    a² - a = a (a - 1) = (a - 1) x a

since a-1 and a are two consecutive whole number, one of them is "even" whole number. Therefore (a² - a) is divisible by 2 for any whole value of a.

2.   2ⁿ + 2ⁿ⁺¹ + 2ⁿ⁺² = 2ⁿ⁻¹ x (2 + 2² + 2³) = 2ⁿ⁻¹ x 14

So, the sum of three consecutive exponents of the number 2 is divisible by 14.

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!