Suppose a company needs temporary passwords for the trial of a new payroll software. Each password will have two digits followed by two letters. The letters J, K, and L and the digits 3 and 6 will not be used. So, there are 23 letters and 8 digits that will be used. Assume that the letters and digits can be repeated. How many passwords can be created using this format?

33,856 passwords can be created using this format

Step-by-step explanation:

Since the letters and the digits can be repeated, for each letter there are 23 possible outcomes and for each digit there are 8 possible outcomes.

There are 2 letters and then 2 digits in the password. So

23*23*8*8 = 33,856

33,856 passwords can be created using this format

42.4

step-by-step explanation:

convert to decimal

answer: it actually depends on which is the independent variable and which is the dependent variable. let us say we're looking at a linear equation. y=2x+3. we theoretically could switch the equation to be x=(y-3)/2 and it would be the same line. so either a causes b or it can be that b causes a. so technically the answer is false

step-by-step explanation: