In a test of effectiveness of garlic for lowering cholesterol, 45 subjects were treated with garlic in process tablet form. chorlesterol levels were measured before and after the treatement. the cahnges in their levels of ldl cholesterol (in mg/dL) have a sample mean 5.1 and a sample standard deviation of 16.7. a.) the best point estimate is _mg/do b.) construct a 99% confidence interval estimate of the mean net change in ldl cholesterol after the garlic treatment. c) interpret this interval

A) the sample mean is the best point estimate 5.1mg/do

B) the required confidence  interval = [ 0.92 , 9.28]

C) the confidence interval suggest that there is a 99% chance that the true value of the mean net change in LDL cholesterol after garlic treatment is contained in the interval

Step-by-step explanation:

information given from the question

The sample size (n) = 45

The mean of the changes ( before and after ) in the levels of the LDL cholesterol = 5.1

the standard deviation = 16.7

B) the 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment can be constructed using the formula

=  

d = sample mean = 5.1

sa = standard deviation = 16.7

= 1.6787

=

= [ 5.1 - 1.6787 * 2.4895, 5.1 + 1.6787 * 2.4895 ]

= [ 5.1 - 4.1791, 5.1 + 4.1791  ]

the required confidence  interval = [ 0.92 , 9.28]

C) the confidence interval suggest that there is a 99% chance that the true value of the mean net change in LDL cholesterol after garlic treatment is contained in the interval

the answer is the option b

the range is all real numbers

step-by-step explanation:

we know that

the absolute value parent function is equal to

see the attached figure to better understand the problem

so

a. it is v-shaped > is true

b. the range is all real numbers > is not true

because the range is the > [0,∞)

all real numbers greater than or equal to zero

c. it goes through the origin > is true

d. the domain is all real numbers > is true

step-by-step explanation:

step-by-step explanation: