Trig please help

Law of Sines and the Ambiguous Case.

In ∆ ABC, a =19, b = 15, and m < A = 50*
How many distinct triangles can be drawn given these measurements?

One

Step-by-step explanation:

19/sin(50) = 15/sinB

sinB = 0.6047719288

B = 37.2°, 142.8°

Since 142.8+50 = 192.8 > 180

Only one triangle can be formed with angle 37.2 at B

the answer is 0.3175 hope that you ^w^

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