2 POINTS) Using the calculation for damage and defects discussed in lecture, calculate the number of standardized sets that must be planned for in order to have 7,500 sets available to the customer each month. (Choose the closest answer) Group of answer choices 7431 7763 7604 7514 7798 7831 7708 7691 7512 7756

7431, 7763, 7604

Step-by-step explanation:

Number of standardized size Z

The observation 7500

Mean U

Standard deviation S

Group 1

7431 7763 7604

U = (7431 + 7763 + 7604)/4

U = -0.736

Z = (X - U)/S

Z = (7500 - 7599.3)/135 = -99.33/135

Z = - 0.736

For first group

Group 2

7514 7798 7831 7708

U = (7514+ 7798+ 7831 +7708 )/4

U = 7712.75

S = 123.27

Z = (X - U)/S

Z = (7500- 7712.75)/123.27 = -212.15/123.27

Z = - 1.721

For second group

Group 3

7691 7512 7756

U = (7691 + 7512 +7756)/3

U = 7652.7

S = 102.84

Z = (X - U)/S

Z = (7500- 7652.7)/102.84 = -152.7/102.84

Z = - 1.4848

For third group

Z1>Z3>Z2

The first group is the answer

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: