Type A is 8 feet tall and grows at a rate of 18 inches per year. Type B is 9 feet tall and grows at a rate of 17 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.

12 years.

Step-by-step explanation:

Le x represent number of years.

We have been given that type A is 8 feet tall and grows at a rate of 18 inches per year. So growth of type A in x years would be inches.

1 feet = 12 inches.

8 feet = 8*12 inches = 96 inches.

9 feet = 9*12 inches = 108 inches.

The total height of type A would be inches.

We are also told that type B is 9 feet tall and grows at a rate of 17 inches per year. So growth of type B in x years would be inches and total height of type B would be inches.

To find the years when both trees will be of the same height, we will equate height of both trees and solve for x as:

Therefore, after 12 years the height of these trees will be the same.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

no

step-by-step explanation: